2/√13=
5/√4=
3/5-√2=
1/7+√5=
1/2√8=
13/4+√2=
2√2/3-√10=
Penjelasan dengan langkah-langkah:
[tex]1). \frac{2}{ \sqrt{3} } \\ = \frac{2 \sqrt{3} }{ \sqrt{3} \sqrt{3} } \\ = \frac{2 \sqrt{3} }{ \sqrt{9} } \\ = \frac{2 \sqrt{3} }{3} [/tex]
[tex]2). \frac{5}{ \sqrt{4} } \\ = \frac{5 \sqrt{4} }{ \sqrt{4} \sqrt{4} } \\ = \frac{5 \sqrt{4} }{ \sqrt{16} } \\ = \frac{5 \sqrt{4} }{4} [/tex]
[tex]3). \frac{3}{5 - \sqrt{2} } \\ = \frac{3(5 + \sqrt{2}) }{(5 - \sqrt{2} )(5 + \sqrt{2)} } \\ = \frac{15 +3 \sqrt{2} }{ {5}^{2} - ( \sqrt{2}) {}^{2} } \\ = \frac{15 + 3 \sqrt{2} }{25 - 2} \\ = \frac{15 + 3\sqrt{2} }{23} [/tex]
[tex]4). \frac{1}{7 + \sqrt{5} } \\ = \frac{1(7 - \sqrt{5} )}{(7 + \sqrt{5} )(7 - \sqrt{5} )} \\ = \frac{7 - \sqrt{5} }{ {7}^{2} - ( \sqrt{5}) {}^{2} } \\ = \frac{7 - \sqrt{5} }{49 - 5} \\ = \frac{7 - \sqrt{5} }{44} [/tex]
[tex]5). \frac{1}{2 \sqrt{8} } \\ = \frac{1}{2 \sqrt{4.2} } \\ = \frac{1}{2.2 \sqrt{2} } \\ = \frac{1}{4 \sqrt{2} } [/tex]
[tex]6). \frac{13}{4 + \sqrt{2} } \\ = \frac{13(4 - \sqrt{2}) }{(4 + \sqrt{2})(4 - \sqrt{2}) } \\ = \frac{52 - 13 \sqrt{2} }{ {4}^{2} - ({ \sqrt{2} )}^{2} } \\ = \frac{52 - 13 \sqrt{2} }{16 - 2} \\ = \frac{52 - 13 \sqrt{2} }{14}[/tex]
[tex]7). \frac{2 \sqrt{2} }{3 - \sqrt{10} } \\ = \frac{2(3 + \sqrt{10} ) \sqrt{2} }{(3 - \sqrt{10} )(3 + \sqrt{10}) } \\ = \frac{(6 + 2 \sqrt{10} ) \sqrt{2} }{ {3}^{2} - ( \sqrt{10} ) {}^{2} } \\ = \frac{6 \sqrt{2} + 2 \sqrt{10} \sqrt{2} }{9 - 10} \\ = \frac{6 \sqrt{2} + 2 \sqrt{20} }{ - 1} \\ = - 6 \sqrt{2} - 2 \sqrt{4 \times 5} \\ = - 6 \sqrt{2} - 2 \times 2 \sqrt{5} \\ = - 6 \sqrt{2} - 4 \sqrt{5} [/tex]
Maaf Ya Kalo Salah
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